Question
A robot probe drops a camera off the rim of a 105.0 m high cliff on Mars, where the free-fall acceleration is -3.70 m/s2. Find the velocity in m/s with which the camera hits the ground.
Answers
drwls
sqrt(2g'H), where g' is the acceleration of gravity on Mars.
sqrt(7.4*105) = 27.9 m/s
sqrt(7.4*105) = 27.9 m/s
Chel
No
karly
42 and 11