Asked by maham
if a ball is thrown horizontally from the top of a cliff and takes 3 seconds to reach the beach below. calculate the height of the cliff by considering the vertical motion only.
answer : s=ut+half at(square)
s=0*3+half*10*3
s=3+45
s=48 m/s(square)
answer : s=ut+half at(square)
s=0*3+half*10*3
s=3+45
s=48 m/s(square)
Answers
Answered by
Damon
a = - 9.8 m/s^2
v = Vi + a t = 0 - 9.8 t
h = Hi + Vi t -(9.8/2) t^2
0 = Hi + 0 (3) - (9.8/2)(3)^2
4.9 (9) = Hi
Hi = 44.1 meters high
v = Vi + a t = 0 - 9.8 t
h = Hi + Vi t -(9.8/2) t^2
0 = Hi + 0 (3) - (9.8/2)(3)^2
4.9 (9) = Hi
Hi = 44.1 meters high
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.