Asked by Kiran
A man throws a ball horizontally from the top of a hill 4.9m high. He wants the ball to clear a fence 2.4m high standing on horizontal surface and 8m horizontally away from the point of projection. Find the minimum speed at which the ball must be thrown.
Answers
Answered by
Steve
Since the horizontal speed is constant, the time it takes to reach the fence is 8/v
The height is
h = 4.9 - 4.9t^2
We want h(t) = 2.4 when t=8/v, so
4.9 - 4.9(8/v)^2 = 2.4
v = 11.2 m/s
The height is
h = 4.9 - 4.9t^2
We want h(t) = 2.4 when t=8/v, so
4.9 - 4.9(8/v)^2 = 2.4
v = 11.2 m/s
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