A styrofoam cup with a mass of 2.97g has 81.68g of hot water at60.0 •C has ice added to it untill it reaches a temrature of 7.0•C and weights 141.12g. What is the molar heat lost by the water to melt the ice.

Question

A styrofoam cup with a mass of 2.97g has 81.68g of hot water at60.0 •C has ice added to it untill it reaches a temrature of 7.0•C and weights 141.12g. What is the molar heat lost by the water to melt the ice. 
Equation: -(mcdeltaT)=(deltaHn)+(mcdeltaT)
m1=81.68g.               DeltaH=?         m=141.12g
c=4.19J/g•C.              n=18.0152mol.  c=4.19
DeltaT=-53•C                                     DeltaT=53•C

DrBob222 · Answer

I don't understand the trouble here. You have the equation and the numbers; all you do is substitute the numbers and turn the crank. Out comes the answer.

nadjima · Answer

nadjima ha hol