Asked by Cassidy

A styrofoam cup with a mass of 2.97g has 81.68g of hot water at60.0 •C has ice added to it untill it reaches a temrature of 7.0•C and weights 141.12g. What is the molar heat lost by the water to melt the ice.
Equation: -(mcdeltaT)=(deltaHn)+(mcdeltaT)
m1=81.68g. DeltaH=? m=141.12g
c=4.19J/g•C. n=18.0152mol. c=4.19
DeltaT=-53•C DeltaT=53•C
Answered by DrBob222
I don't understand the trouble here. You have the equation and the numbers; all you do is substitute the numbers and turn the crank. Out comes the answer.
Answered by nadjima
nadjima ha hol
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