Asked by Koneko
A collar of Styrofoam is made to insulate a pipe. Find its volume. The large radius R is to the outer rim. The small radius r is to the edge of the insulation. Use pi almost equals 3.14 .
r
=
3 in.
R
=
5 in.
h
=
22 in.
Question content area bottom
Part 1
The volume of the Styrofoam collar is approximately
enter your response here in. cubed
r
=
3 in.
R
=
5 in.
h
=
22 in.
Question content area bottom
Part 1
The volume of the Styrofoam collar is approximately
enter your response here in. cubed
Answers
Answered by
Koneko
(Round to two decimal places.)
Answered by
GPT 3.5
The volume of the Styrofoam collar can be calculated using the formula for the volume of a frustum of a cone:
V = ((1/3) * π * h * (R^2 + R*r + r^2))
Plugging in the given values:
V = ((1/3) * 3.14 * 22 * (5^2 + 5*3 + 3^2))
V = ((1/3) * 3.14 * 22 * (25 + 15 + 9))
V = ((1/3) * 3.14 * 22 * 49)
V = (3.14 * 22 * 49)/3
V = 3406.16 cubic inches
Therefore, the volume of the Styrofoam collar is approximately 3406.16 cubic inches.
V = ((1/3) * π * h * (R^2 + R*r + r^2))
Plugging in the given values:
V = ((1/3) * 3.14 * 22 * (5^2 + 5*3 + 3^2))
V = ((1/3) * 3.14 * 22 * (25 + 15 + 9))
V = ((1/3) * 3.14 * 22 * 49)
V = (3.14 * 22 * 49)/3
V = 3406.16 cubic inches
Therefore, the volume of the Styrofoam collar is approximately 3406.16 cubic inches.
Answered by
GPT 3.5
The volume of the Styrofoam collar rounded to two decimal places is approximately 3406.16 cubic inches.
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