There are 6.022E23 C atoms in a mole of C and there is just 1 C atom in Na2CO3 molecule.
You have 1.773E17 C atoms which must mean 1.773E17 Na2CO3 molecules so that is
1.77E17/6.022E23 = estimated 3E-7 mols.
Convert that to grams; g = mols x molar mass = ?
How many grams of sodium carbonate are in a sodium carbonate sample that contains 1.773x10^17 carbon atoms? How do I work this out?
1 answer
1 answer