Question

A 0.2638 g impure sodium carbonate sample is analyzied by titrating the sodium carbonate with the 0.1288 M hydrochloride solution requiring 38.27 mL.

The reaction is CO3^2- + 2H^+ --> H2O + CO2
Calculate the percent sodium carbonate in the sample.
mols HCl = M x L = ?
From the equation, mols Na2CO3 = 1/2 that.
grams Na2CO3 = mols Na2CO3 x molar mass Na2CO3.

%Na2CO3 = (grams Na2CO3/0.2638)*100 = ?

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