Asked by sam
A 52.2 kg parachutist lands moving straight downward with a speed of 3.75 m/s. If the parachutist comes to rest with constant acceleration over a distance of 0.794 m, what force does the ground exert on her?
Answers
Answered by
Damon
average speed during crash = 3.75/2
so
time to stop = .794 / (3.75/2)
acceleration = change in speed / change in time
or
a = (0 - -3.75) / [.794 / (3.75/2) ]
and
F = m a = 52.2 a
so
time to stop = .794 / (3.75/2)
acceleration = change in speed / change in time
or
a = (0 - -3.75) / [.794 / (3.75/2) ]
and
F = m a = 52.2 a
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.