Vf^2 = Vo^2 + 2gd,
Vf^2 = (19.6)^2 + 2*9.8*41.6 = 1199.52,
Vf = 34.6m/s.
A parachutist descending at a speed of 19.6
m/s loses a shoe at an altitude of 41.6 m.
What is the velocity of the shoe just before
it hits the ground? The acceleration of gravity
is 9.81 m/s2.
Answer in units of m/s
2 answers
When does the shoe reach the ground? Answer in seconds.