A juggler throws a ball with an initial horizontal velocity of +1.1 m/s and an initial vertical velocity of +5.7 m/s. What is its acceleration at the top of its flight path? Make sure to consider the sign when responding. Consider the upward direction as positive.

What equation would I use to solve this problem?

1 answer

Hey, look, this is a phony trick question.
There is only one force in this problem, gravity, m g
Therefore there is only one acceleration in this problem, g , which is about -9.81 m/s^2 on earth.
There is NO HORIZONTAL ACCELERATION
There is no change in vertical acceleration until it hits the ground.
It is -9.81 forever and ever and always !