Asked by Anonymous
2/3 of miss lina's class were boys. there were between 2 and 14 boys. One day, twin girls joined the class. Now 3/5 of the students are boys. how many students are in miss lina's class now?
Answers
Answered by
Steve
If there were originally b boys out of s students in the class,
b/s = 2/3
b/(s+2) = 3/5
Or,
b = 2s/3
5b = 3s+6
So,
5(2s/3) = 3s+6
10s = 9s+18
s = 18
Now you should be able to answer the question.
b/s = 2/3
b/(s+2) = 3/5
Or,
b = 2s/3
5b = 3s+6
So,
5(2s/3) = 3s+6
10s = 9s+18
s = 18
Now you should be able to answer the question.
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