Asked by Lovely
What horizontal force is needed to push a hospital bed of mass 120 kg at a constant speed up a smooth sloping plane inclined at an angle of 37 degrees above the ground?
Answers
Answered by
Henry
m*g = 120kg * 9.8N/kg = 1176 N. = Wt. of
the bed.
Fp = 1176*sin37 = 707.73 N. = Force
parallel to the incline.
Fn = 1176*cos37 = 939.20 N. = Normal =
Force perpendicular to the incline.
Fap-Fp = m*a
Fap-707.73 = m*0 = 0
Fap = 707.73 N. = Force applied parallel
to the incline.
Fx = Fap*cos A = 707.73*cos37 = 565 N.
= Hor. force applied.
the bed.
Fp = 1176*sin37 = 707.73 N. = Force
parallel to the incline.
Fn = 1176*cos37 = 939.20 N. = Normal =
Force perpendicular to the incline.
Fap-Fp = m*a
Fap-707.73 = m*0 = 0
Fap = 707.73 N. = Force applied parallel
to the incline.
Fx = Fap*cos A = 707.73*cos37 = 565 N.
= Hor. force applied.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.