Asked by Danielle

The level of water in a rectangular swimming pool needs to be lowered 4.00 inches. If the pool is 36.50 ft long and 15.00 ft wide, and the water is siphoned out at a rate of 5.0 gal/min, how long will the siphoning take?
1 ft^3 = 7.48 gal.
Answered by bobpursley
volum of water removed: 1/3 ft x 36.5ft x 15ft.

calculate that volume

Now convert ft^3 to gal. there are 7.48 gallons per ft^3

Now,

time=volumeinGallons/ratepump
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