Asked by malical

1. WATER At 2 P.M., the level of the water in the pool was 10 feet. At 6 P.M., the level of water was 2 feet. Find the constant rate of change of the water.
Answered by Ms. Sue
In 4 hours the water decreased 8 feet.

How much did it decrease per hour?
Answered by henry2,
r = (2-10)/4 = -8/4 = -2Ft/h.
The water decreased at a rate of 2 ft. per hour.
















































































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