Asked by Austine
The water level in a spherical bowl has a diameter of 30cm. If the horizontal diameter of the bowl is 10cm below the water level. calculate the radius of the bowl and the depth of the water in the bowl.
Answers
Answered by
Reiny
sketch a cross-section, and complete the right-angled triangle
let the radius be r
r^2 = 10^2 + 15^2
r = √325
depth of water = 10 + √325
= ...
let the radius be r
r^2 = 10^2 + 15^2
r = √325
depth of water = 10 + √325
= ...
Answered by
Anonymous
18.303
Answered by
Emmanuel
Let the radius be r
R^2=5^2+15^2
R =√250
R =15.8
Depth of water = 5 + 15.8
= 20.8
R^2=5^2+15^2
R =√250
R =15.8
Depth of water = 5 + 15.8
= 20.8
Answered by
Paul
I want to see how the diagram we look out on this question. Please reply it.
The water level in a spherical bowl has a diameter of 30cm. If the horizontal diameter of the bowl is 10cm below the water level. calculate the radius of the bowl and the depth of the water in the bowl.
The water level in a spherical bowl has a diameter of 30cm. If the horizontal diameter of the bowl is 10cm below the water level. calculate the radius of the bowl and the depth of the water in the bowl.
Answered by
Anonymous
Please I want to see how the diagram is on this question
Answered by
Anonymous
Please I want to see the diagram to this question answered above
Answered by
Sophie
Please I want to see how the question is going to be solved and how the diagram is drawn
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