Question
100.0g of 4.0c water is heated until its temperature is 37c. if the specific heat of water is 4.18 j/g c, calculate the amount of heat energy needed to cause this rise in temperature.
Answers
q = mass H2O x specific heat x (Tfinal-Tinitial)
YOu know mass, specific heat, Tfinal and Tinitial. Solve for q.
YOu know mass, specific heat, Tfinal and Tinitial. Solve for q.
13,794
m = 100g
c = 4.18
∆T = 33°C
Q = mc∆T
Q = 100g * 4.18 * 33°C
= 13794J
c = 4.18
∆T = 33°C
Q = mc∆T
Q = 100g * 4.18 * 33°C
= 13794J
Compare the energy needed to raise the temperature of 1kg of water from 20°C to 100°C and the energy needed to boil 1 kg of water at 100°C
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