Question

200 g of water is heated in a copper calorimeter with a mass of 100 g. If the water has an initial temperature of 30 ºC and a final temperature of 40 ºC, calculate the heat energy absorbed by the water? The specific heat capacity of water is 4200 J/ kg °C.

Answer 1

To calculate the heat energy absorbed by the water, we need to use the formula:

Q = mcΔT

where Q is the heat energy absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature of the water.

First, let's calculate the change in temperature of the water:

ΔT = final temperature - initial temperature
ΔT = 40 ºC - 30 ºC
ΔT = 10 ºC

Now, we can plug in the values:

Q = mcΔT
Q = (0.2 kg)(4200 J/kg °C)(10 ºC)
Q = 840 J

Therefore, the heat energy absorbed by the water is 840 J.