Question
Charge A has a charge of +2 C. Charge B has a charge of - 3 C and is located 1 meter to the right of A. Charge C is located 1 m to the right of charge Band has a charge of -1C. If a fourth charge (Charge D) is placed 4 m to the right of Charge B, How much charge must it havefor the net force on Charge B to be zero?
Answers
does not matter what the charge on B is, call it -1 and call k = 1
To the left
2/(1)^2 + 1/(1)^2 = 3/1 to the left
so we need 3 to the right
Qd/4^2 = 3
Qd = 16*3 = 48
To the left
2/(1)^2 + 1/(1)^2 = 3/1 to the left
so we need 3 to the right
Qd/4^2 = 3
Qd = 16*3 = 48
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