Asked by Celine
A point charge with a charge of q1=2.60uC is held stationary at the origin. A second point charge with charge q2=-4.70uC moves from the point. x=0.140m, y=0 to the point
x=0.230m, y=0.290m
How much work is done by the electric force on q2?
x=0.230m, y=0.290m
How much work is done by the electric force on q2?
Answers
Answered by
bobpursley
Work is conservative, so do the x first, then the y.
work=INT f.dx + int f.dy
= INTkq1q2/x^2 dx+ int kq1q2/y^2 dy
= kq1q1 (1/x)over limits + kq1q2 (1/y)over limits
limits x .140 to .230 ; y 0 to .290
work=INT f.dx + int f.dy
= INTkq1q2/x^2 dx+ int kq1q2/y^2 dy
= kq1q1 (1/x)over limits + kq1q2 (1/y)over limits
limits x .140 to .230 ; y 0 to .290
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