Asked by Dulce

dETERMINE the horizontal force needed to accelerate a 50 kg grocery cart from rest to 0.90 m/s in 2.8s if the coefficient of friction between the cart and the floor is 0.20?
Answered by Damon
a = (.90 -0)/2.8

weight = m g = 50 (9.81)

friction force = .2 * 50 (9.81)

F - .2*50(9.81) = 50 (.9)/2.8
Answered by Dulce
did the sign * is for multplication?
Answered by Damon
yes * means "times"
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