Asked by Dulce
dETERMINE THE HORIZONTAL FORCE needed to accelerate a 50kg grocery cart from rest to 0.90 m/s in 2.8s if the coefficient of friction between the cart and the floor is 0.20 ?
Answers
Answered by
Henry
m*g = 50kg * 9.8N/kg = 490 N. = Wt. of
cart.
Fk = u*mg = 0.2 * 490 = 98 N. = Force of
kinetic friction.
a=(V-Vo)/t = (0.90-0)/2.8 = 0.321 m/s^2/
F-Fk = m*a
F - 98 = 50*0.321 = 16.07
F = 16.07+98 = 114.1 N.
cart.
Fk = u*mg = 0.2 * 490 = 98 N. = Force of
kinetic friction.
a=(V-Vo)/t = (0.90-0)/2.8 = 0.321 m/s^2/
F-Fk = m*a
F - 98 = 50*0.321 = 16.07
F = 16.07+98 = 114.1 N.
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