Question

1. The quadratic equation -3x^2 – x = 10 has two real solutions. (true or False) Justify your answer.
2. If (2x – 3) (x + 5) = 8, then either 2x – 3 = 8 or x + 5 = 8. (True or False) Justify your answer.

Answer 1

-3x^2 – x = 10
3x^2 + x + 10=0
the discriminant is
b^2 - 4ac
= 1 - 4(3)(1) which is negative, so

there are two complex solutions, and the statement is false

2. again it is false,
it would be true if the right side = 0 and not 8
or take one the answers,
x+5 = 8
x = 3
sub that into the original
LS = (6-3)(3+5)
= 3(8) = 24
RS = 8
LS ≠ RS, the statement is false

Answer 2

Thank you so much Reiny. I clearly understood it.