Asked by Brandi
Calculate the molarity of the following aqueous solution of 25.0 grams of MgBr2 in 0.355 L solution?
Did I work this right?
25gMgBr2/184.113 gMgBr2
=.1357861748 mol MgBr2
then:
.1357861748 mol MgBr2/0.355 L
=.382 M
Did I work this right?
25gMgBr2/184.113 gMgBr2
=.1357861748 mol MgBr2
then:
.1357861748 mol MgBr2/0.355 L
=.382 M
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