Calculate the molarity of the following aqueous solution of 25.0 grams of MgBr2 in 0.355 L solution?

Question

Did I work this right?
25gMgBr2/184.113 gMgBr2
=.1357861748 mol MgBr2

then:
.1357861748 mol MgBr2/0.355 L
=.382 M

Answer 1

It looks ok to me but you don't need all of those intermediate numbers.

Answer 2

Thank you DrBob222! :)