Question
Calculate the molarity of 12.5g of sucrose (C12H22O11) in 80mL of solution.
12.01 x 12 = 144.12
1.01 x 22 = 22.22
16.00 x 11 = 176.00
-------------------
342.34
12.5g
----- / 342.34 = 0.003/80 = 4.56
80mL
12.01 x 12 = 144.12
1.01 x 22 = 22.22
16.00 x 11 = 176.00
-------------------
342.34
12.5g
----- / 342.34 = 0.003/80 = 4.56
80mL
Answers
DrBob222
Due to the spacing problem I can't tell if all is ok or not; however, I suspect most of it is. The correct answer is 0.456 M You should have divided by L and not mL.
Then M = mols/L = ? above/0.080 - 0.456
mols sucrose = 12.5/342 = approx 0.0365
M = mols/L = 0.0365/0.080 = approx 0.456
Then M = mols/L = ? above/0.080 - 0.456
mols sucrose = 12.5/342 = approx 0.0365
M = mols/L = 0.0365/0.080 = approx 0.456