Asked by Lisa
9w-w^3 I need someone to explain step by step how do I factor this problem
Answers
Answered by
Steve
first note that each term has a w in it, so
w(9-w^2)
Now recall that a^2-b^2 = (a-b)(a+b), so since 9-w^2 is the difference of two squares (3^2-w^2), we have
w(3-w)(3+w)
w(9-w^2)
Now recall that a^2-b^2 = (a-b)(a+b), so since 9-w^2 is the difference of two squares (3^2-w^2), we have
w(3-w)(3+w)
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