Question
Four students at a computer fair competed against each other in a space-travel game. Chris scored 2/3 as many points as the winner Pat. Rich scored 1/2 as many points as Chris. Tome scored 100 points, which was 90 points less than Rich's score. How many points did Pat score?
Answers
what do we know?
c = 2/3 p
r = 1/2 c
t = 100 = r-90
So, what is p?
p = 3/2 c
= 3/2 (2r) = 3r
= 3(t+90)
= 3(190)
= 570
c = 2/3 p
r = 1/2 c
t = 100 = r-90
So, what is p?
p = 3/2 c
= 3/2 (2r) = 3r
= 3(t+90)
= 3(190)
= 570
Pat - x
Chris - 2/3x
Rich - 1/2*2/3x = 1/3x
Tom - 1/3x - 90 = 100
1/3x = 190
x = 570
Chris - 2/3x
Rich - 1/2*2/3x = 1/3x
Tom - 1/3x - 90 = 100
1/3x = 190
x = 570
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