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Asked by Jordan

You buy a new computer for $2100. The computer is decreases by 5% annually. When will the computer have a value of $600?


Y = a(1+r/n)^n(t)
8 years ago

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Answered by Jordan
Y = 5.25
8 years ago
Answered by Steve
You want t years, where

2100(0.95)^t = 600
0.95^t = 2/7
t = log(2/7)/log(0.95) = 24.42
8 years ago
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You buy a new computer for $2100. The computer is decreases by 5% annually. When will the computer have a value of $600?


Y = a(1+r/n)^n(t)

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