Question

a wheel rotating at 1800 rpm slows down uniformly to 1200 rpm in 2.0 sec. calculate a)the angular acceleration (revs/s^2) of the motor. and b) the number of revolutions it makes in this time.

Answer 1

number of revolutions:

d=avgspeed*time=1500rpm*2/60 min

acceleration:
wf=wi+at
a= (wf-wi)/t=600rpm*2PIrad/rev*1m/60sec*1/2sec

Answer 2

Good