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If a wheel revolving at 1800 r.p.m. slows down uniformly to 1200 r.p.m. in 25s, calculate the angular acceleration of the wheel and the number of revolutions it makes in this time.
8 years ago

Answers

Anonymous
1800 rev/min * 2 pi rad/rev * 1 min/60 s = Omegai
1200 similarly ---> Omegaf

d omega = (Omegaf-omegai)
dt = 25 s

so
d Omega/dt = alpha = d omega/dt

average angular velocity
= (Omagaf+Omegai)/2
total radians = average vel * 25 sec

total revs = total radians/2pi
8 years ago

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