Question
a 60g golf ball leaves the face of the club with a velocity of 75m/s. if the club exerted an average force of 3.0x10to the 4th N, what was the time of impact between the club and the ball?
Answers
Henry
F = m*a
a = F/m = 3.0*10^4/0.06 = 5*10^5 m/s^2.
a = (V-Vo)/t = 5*10^5 m/s^2
(75-0)/t = 5*10^5
5*10^5t = 75
t = 1.5*10^-4 s.
a = F/m = 3.0*10^4/0.06 = 5*10^5 m/s^2.
a = (V-Vo)/t = 5*10^5 m/s^2
(75-0)/t = 5*10^5
5*10^5t = 75
t = 1.5*10^-4 s.