Question

A golf ball leaves a tee at 60n/s and strikes the ground 200m away. At what two angles with the horizontal could it have begin its flight? Find the timed of flight and maximum attitude in each case.

Answers

R_scott
let's use m/s instead of n/s

the range equation is ... R = u^2 * sin(2θ) / g
... u is the launch velocity, and θ is the launch angle

solving for θ ... sin(2θ) = R * g / u^2
... there are two solutions

find the two possible vertical velocities ... u * sin(θ)

the flight times (t) are ... t = [2 * u * sin(θ)] / g

the max altitudes are ... 1/2 * g * t^2
Billy bob
What's the answer? It's for college

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