Asked by Mike
A 38.9 g piece of iron at 84.6oC is placed in a beaker containing 179.7 g of 20.7oC water. What is the final temperature (oC)of the water?
Answers
Answered by
DrBob222
heat lost by Fe + heat gained by H2O = 0
[mass Fe x specific heat Fe x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for Tfinal H2O
You may need to look up specific heat Fe and H2O if they aren't given in the problem.
[mass Fe x specific heat Fe x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for Tfinal H2O
You may need to look up specific heat Fe and H2O if they aren't given in the problem.
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