Question
A piece of iron has a temperature of 0 zero degrees Celsius. At what temperature would the iron atoms have twice as much kinetic energy?
Answers
Arora
K.E. = (3/2)*k*T, where k is the Boltzman constant.
You must always take temperature in Kelvin, so the given temperature is 273K
=> (K.E.1) = (3/2)*k(273)
=> (K.E.2) = 2(K.E.1) = 2*(3/2)*k*(273)
= (3/2)*k*(2*273)
= (3/2)*k*(546)
The new temperature is double the old, since temperature and K.E. are directly proportional. The required temp. is 546K, or 273 degrees Celsius.
You must always take temperature in Kelvin, so the given temperature is 273K
=> (K.E.1) = (3/2)*k(273)
=> (K.E.2) = 2(K.E.1) = 2*(3/2)*k*(273)
= (3/2)*k*(2*273)
= (3/2)*k*(546)
The new temperature is double the old, since temperature and K.E. are directly proportional. The required temp. is 546K, or 273 degrees Celsius.