Asked by Anonymous
how do you find algebraically the measure of the obtuse angle, to the nearest degree, that satisfies the equation 3 sec theta = 5
is it sec theta = 5/3 and then cos -1 (5/8) = 0.4
is it sec theta = 5/3 and then cos -1 (5/8) = 0.4
Answers
Answered by
Reiny
3secØ = 5
secØ = 5/3
then cosØ = 3/5 , since secA = 1/cosA
Ø = arccos 3/5 = appr53.13°
but you wanted the obtuse angle, so
Ø = 360-53.13 = 306.87° , because the cosine is positive in quadrant I and IV
to the nearest degree it would be 307°
secØ = 5/3
then cosØ = 3/5 , since secA = 1/cosA
Ø = arccos 3/5 = appr53.13°
but you wanted the obtuse angle, so
Ø = 360-53.13 = 306.87° , because the cosine is positive in quadrant I and IV
to the nearest degree it would be 307°
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.