Asked by Sarah
Find derivative using logarithmic differentiation
F(x)= secx^cotx
F(x)= secx^cotx
Answers
Answered by
Steve
f = secx^cotx
log f = cotx * log secx
1/f f' = (-csc^2 x * log secx) + (cotx * secx*tanx/secx)
f' = secx^cotx (1 - csc^2(x) log secx)
log f = cotx * log secx
1/f f' = (-csc^2 x * log secx) + (cotx * secx*tanx/secx)
f' = secx^cotx (1 - csc^2(x) log secx)
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