Ask a New Question

Asked by Njau

Resolve a force of 7.5N acting at an angle 40 to its horizontal an vertical components.
11 years ago

Answers

Answered by Devron
Horizontal=7.5N*Cos(40)

Vertical=7.5N*Sin(40)
11 years ago
Answered by Valerie
Horizontally =7.5 N*Cos(40)=5.75N


Vertically =7.5N*Sin(40)=4.82N
3 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

What is the net force acting on the ring in the diagram? <img src="/images/1261797426.jpg" width=... resolve a force of 120n acting at an angle of 30degree with respect to horrizontal. can a force of IN acting over an area of 1m^2 called The force F sub x acting on a particle is shown as a function of X. If an object starts at the ori... Force of 2.25N is acting on charge 15x10^-4C at any point. Find the Electric Field Intensity at that... Resolve a force of 23 N at 180 degrees and a force of 47 N at 270 degrees. What is the net force acting on the object below? Its a square and on the left side it has to 5's... Resolve a force of 100 n in to two compound of 200 n each drow sketch .solve this resolve a force of 200N inclined at 60 degree to the horizontal and vertical component. What is the net force acting on the object below? * 1 point Captionless Image 25 N 5 N 10 N
Submit Your Answer

Question

Resolve a force of 7.5N acting at an angle 40 to its horizontal an vertical components.

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use