Asked by Sonya
A force of 800 N stretches a spring a distance 0.200 m horizontally. a) What is the potential energy of the spring when it is stretched 0.200m b) What is its potential energy when it is compressed 5.00cm This is a conservation of energy problems. The potential is elastic and not gravitational because the spring does not work against gravity as it moves horizontally
Answers
Answered by
Devron
F of spring=kx
Where:
x=0.200m
and
F=800N
Solve for k:
k=800/0.200m
k=4,000
a.)
PE=1/2kx^2
PE=1/2(4,000)(0.200m)
PE=400J
b.)
PE=1/2kx^2
PE=1/2(4,000)(0.0500m)
PE=100J
****Check my math.
Where:
x=0.200m
and
F=800N
Solve for k:
k=800/0.200m
k=4,000
a.)
PE=1/2kx^2
PE=1/2(4,000)(0.200m)
PE=400J
b.)
PE=1/2kx^2
PE=1/2(4,000)(0.0500m)
PE=100J
****Check my math.
Answered by
Anonymous
5+9
Answered by
peanut butter
search for a youtube video titled "A force of 800 N stretches a certain spring a distance of 0.200 m" by jonathan david
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