a force of 0.8N stretches an elastic spring by 2cm. find the force constant.

f
e
=
k=?
f=ke
0.8=0.02 * k
k=0.8/0.02
k=40N/m

10 answers

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A FORCE OF 0.8N STRECHES AN ELASTIC SPRIG BY 2CM .FIND THE ELASTIC CONSTANT OF THE SPRING
F=0.8, E=2CM=2\100=0.02M, KG=? ,F=KE ,K=F\E=0.8\0.02=40NM
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40 _ 8 m
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Vb
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0.4
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