Asked by Jennifer

What are the foci of the hyperbola with equation 16y^2-9x^2=144
Answered by Steve
y^2/9 - x^2/16 = 1

so, what are the foci of y^2/a^2 - x^2/b^2 = 1?
Answered by Anonymous
why cant you just give the answer?!?!?!?!?!?
Answered by Anonymous
Answer is (0plus or minus 5)
Answered by Meagan
16y + 0 = 16y
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