Asked by Alex
The specific heat of copper is 0.385 J/g.°C. Which equation would you use to calculate the amount of heat needed to raise the temperature of 0.75 g of copper from 7°C to 29°C?
a. Q = 0.385 J/g.°C ` (29°C 7°C)
b. Q = 0.75 g ` 0.385 J/g.°C ` 29°C
c. Q = 0.75 g ` 0.385 J/g.°C ` 22°C
d. Q = 0.75 g ` 0.385 J/g.°C ` 7°C
Please help me, I seriously do not understand formulas/equations and I'm studying for a big test!
a. Q = 0.385 J/g.°C ` (29°C 7°C)
b. Q = 0.75 g ` 0.385 J/g.°C ` 29°C
c. Q = 0.75 g ` 0.385 J/g.°C ` 22°C
d. Q = 0.75 g ` 0.385 J/g.°C ` 7°C
Please help me, I seriously do not understand formulas/equations and I'm studying for a big test!
Answers
Answered by
Devron
q=m*c*change in temperature
Where
m=mass
c=specific heat
change in temperature=final temp-initial temp=29C-7C=22 C
You can figure it out from here.
Where
m=mass
c=specific heat
change in temperature=final temp-initial temp=29C-7C=22 C
You can figure it out from here.
Answered by
DrBob222
Just because this may be a little foreign don't let it intimidate you. It's a matter of plugging in the numbers. The formula is
q = mass x specific heat x (Tfinal-Tinitial).
The numbers are
mass = 0.75g from the problem.
specific heat = 0.385 J/g*C from the problem.
Tf = 29 from the problem.
Ti = 7 from the problem.
Now just plug in the numbers.
So q = 0.75 x 0.385 x (29-22) and the closest to that is
0.75 x 0.385 x 22 which is c. The Tf - Ti has been combined from 29-7 to 22.
q = mass x specific heat x (Tfinal-Tinitial).
The numbers are
mass = 0.75g from the problem.
specific heat = 0.385 J/g*C from the problem.
Tf = 29 from the problem.
Ti = 7 from the problem.
Now just plug in the numbers.
So q = 0.75 x 0.385 x (29-22) and the closest to that is
0.75 x 0.385 x 22 which is c. The Tf - Ti has been combined from 29-7 to 22.
Answered by
Alex
Thank you both very much!
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