Asked by Annie
Copper has a specific heat of 0.3845 J/g*C. How much change in temperature would the addition of 35,000 Joules of heat have on a 538.0 gram sample of copper?
Answers
Answered by
DrBob222
q = mc*delta T
35,000 = 538.0 x 0.3845*delta T
Solve for delta T.
35,000 = 538.0 x 0.3845*delta T
Solve for delta T.
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