the length of a rectangle is 2 more than the width, the area of the rectangle is 15 ft. squared . find the length and width.
2 answers
well since 15 = 3*5, I guess that pretty well solves the problem, no?
Width = W Ft.
Length = (W+2) Ft.
Area = (W+2)*W = 15Ft^2
W^2 + 2W - 15 = 0
C = -15 = -3*5
(W-3)(W+5) = 0
W-3 = 0
W = 3
W+5 = 0
W = -5. The width can't be negative.
Therefore, W = 3 Ft.
Length = W+2 = 3 + 2 = 5 Ft.
Length = (W+2) Ft.
Area = (W+2)*W = 15Ft^2
W^2 + 2W - 15 = 0
C = -15 = -3*5
(W-3)(W+5) = 0
W-3 = 0
W = 3
W+5 = 0
W = -5. The width can't be negative.
Therefore, W = 3 Ft.
Length = W+2 = 3 + 2 = 5 Ft.