Asked by Anonymous

The length of the rectangle is 4 more than twice its width and its perimeter is 70m. What are the dimensions of the rectangle?
Answered by John
let x = witdth
4x+2 = length

perimeter of rectangle = 2L + 2W
substitute:
34 = 2(4x+2) +2x
34 = 8x + 4 + 2x
34-4 = 10x
10x = 30
x = 3 - width

length = 4(3) + 2
= 12 + 2 = 14 :)
Answered by Writeacher
John, why isn't the length 2x + 4 ??
Answered by Reiny
Good catch
John has his definition backwards, thus his answer is not correct

width --- x
length ---- 2x+4

2x + 2(2x+4) = 70
6x + 8 = 70
6x = 62
x = 31/3 or 10 1/3

width = 31/3
length = 2(31/3)+4 = 74/3 or 24/2/3

check: 2(31/3) + 2(74/3) = 70
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