Asked by Bea
Assume you poured 5.00 g of KOH in 250 mL of pure water. What is the molarity of the solution you made?
Answers
Answered by
Devron
1 mole of KOH=56.11g
and
250mL=0.250L
Solve for moles:
5.00g*(1 mole/56.11g)= moles of KOH
Molarity=moles/volume (L)
and
250mL=0.250L
Solve for moles:
5.00g*(1 mole/56.11g)= moles of KOH
Molarity=moles/volume (L)
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