Asked by Anonymous
How many grams of lithium fluoride must be added to 3.5 kg of water to make a solution with a molality of 2.0 molal?
Answers
Answered by
DrBob222
m = mols/kg solvent
2.0 = mols/3.5
Solve for mols, then
mol = grams/molar mass. You know m and molar mass, solve for grams.
2.0 = mols/3.5
Solve for mols, then
mol = grams/molar mass. You know m and molar mass, solve for grams.
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