how many grams of lithium metal is required in 410 grams of CA(NO3)2

Answer 1

none. I think you wrote only part of the problem.

Answer 2

consider the reaction in which 410 grams of Ca(NO3)2 react with just the right amount of lithium metal in a single replacement reaction.
1-how many grams of lithium are required?
2- how many grams of each product can be produced?

Answer 3

answered above.