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how many grams of lithium metal is required in 410 grams of CA(NO3)2
15 years ago

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DrBob222
none. I think you wrote only part of the problem.
15 years ago
jack
consider the reaction in which 410 grams of Ca(NO3)2 react with just the right amount of lithium metal in a single replacement reaction.
1-how many grams of lithium are required?
2- how many grams of each product can be produced?
15 years ago
DrBob222

answered above.
15 years ago

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