Asked by Anonymous

how many grams of lithium metal is required in 410 grams of CA(NO3)2
Answered by DrBob222
none. I think you wrote only part of the problem.
Answered by jack
consider the reaction in which 410 grams of Ca(NO3)2 react with just the right amount of lithium metal in a single replacement reaction.
1-how many grams of lithium are required?
2- how many grams of each product can be produced?
Answered by DrBob222

answered above.
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