Asked by archit
A wire of uniform thickness with a resistance of 27 ohm is cut into three equal pieces and are joint in parallel.find the resistance of the parallel combination.
Answers
Answered by
Henry
R = 27Ohm/3 = 9 Ohms.
r =
Answered by
Henry
Correction:
R1 = R2 = R3 = 27/3 = 9 Ohms, each.
When connected in parallel:
Re = 9/3 = 3 Ohms.
R1 = R2 = R3 = 27/3 = 9 Ohms, each.
When connected in parallel:
Re = 9/3 = 3 Ohms.
Answered by
chandradhar
given:
A wire of uniform thickness with a resistance =27 ohm
find:
equivalent resistance in parallel
solution:
resistance of each wire=27/3=9
therefore when in parallel equivalent resistance=
1/rp=1/9+1/9+1/9
=3/9=1/3
therefore rp=3 ohm
A wire of uniform thickness with a resistance =27 ohm
find:
equivalent resistance in parallel
solution:
resistance of each wire=27/3=9
therefore when in parallel equivalent resistance=
1/rp=1/9+1/9+1/9
=3/9=1/3
therefore rp=3 ohm
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