Question

A uniform horizontal wire with a linear mass density of 0.48 g/m carries a 1.9 A current. It is placed in a constant magnetic field, with a strength of 3.5 10-3 T, that is horizontal and perpendicular to the wire. Neglect the magnetic field of the Earth.
(a) As the wire moves upward starting from rest, what is its acceleration?


m/s2

Answer 1

Net force F = F(Ampere) –m•g = I•L•B•sinα –d•L.
(sinα = 1, d =0.48•10^-3 kg/m)
F = m•a =d•L•a
I•L•B –d•L = d•L•a.
a =(I •B) /d – 1.