Asked by Anonymous
the metal gold, with an atomic radius of 144.2pm crystallizes in a face-centered cubic lattice. what is the density of gold?
Answers
Answered by
DrBob222
What is it you don't understand about this problem. We can take it from there. Post any work you've done on this problem.
Answered by
Anonymous
volume=1.442x10^-8cm
4atoms per cell so,
4x (1/6.022x10^23) x 196.97g = 1.31x10^-21 g of gold
cell volume=(1.442x10^-8cm)^3= 2.99x10^-24
density=(1.31x10^-21)/(3.0x10^-24)=438g/cm^3
4atoms per cell so,
4x (1/6.022x10^23) x 196.97g = 1.31x10^-21 g of gold
cell volume=(1.442x10^-8cm)^3= 2.99x10^-24
density=(1.31x10^-21)/(3.0x10^-24)=438g/cm^3
Answered by
DrBob222
144.2 pm = 1.442E-8 cm and that's the RADIUS.
volume of sphere is (4/3)*pi*r^3.
See if that gets you off on the right foot?
volume of sphere is (4/3)*pi*r^3.
See if that gets you off on the right foot?
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