Question

the metal gold, with an atomic radius of 144.2pm crystallizes in a face-centered cubic lattice. what is the density of gold?
What is it you don't understand about this problem. We can take it from there. Post any work you've done on this problem.
volume=1.442x10^-8cm
4atoms per cell so,
4x (1/6.022x10^23) x 196.97g = 1.31x10^-21 g of gold
cell volume=(1.442x10^-8cm)^3= 2.99x10^-24
density=(1.31x10^-21)/(3.0x10^-24)=438g/cm^3
144.2 pm = 1.442E-8 cm and that's the RADIUS.
volume of sphere is (4/3)*pi*r^3.
See if that gets you off on the right foot?

Related Questions

what is the volume of the unit cell? A metal crystallizes in a face-centered cubic lattice. The r... The density of an unknown metal is 1.55 and its atomic radius is 0.197 . It has a face-centered cub... the density of an unknown metal is 2.64 g/cm^3 and its atomic radius is 0.215 nm. It has a face-cent... Aluminum metal crystallizes in a face centered cubic lattice. If each Al atom has a radius of 1.43 A...