Question
A metal, M, of atomic mass 91 amu reacts with fluorine to form a salt that can be represented as MFx. In order to determine x and therefore the formula of the salt, a boiling point elevation experiment is performed. A 9.05-g sample of the salt is dissolved in 100.0 g of water and the boiling point of the solution is found to be 374.54 K. Find the formula of the salt. Assume complete dissociation of the salt in solution.
Is the answer not MF_3??
Is the answer not MF_3??
Answers
bobpursley
assume it is MF3. then
bpe=.52*4*9.05/(.1*(91+3*19))
bpe=18.8/(14.8)=1.2 check that.
Is that equivalent to a new bp of 374.54K?
bpe=.52*4*9.05/(.1*(91+3*19))
bpe=18.8/(14.8)=1.2 check that.
Is that equivalent to a new bp of 374.54K?
Anonymous
It is not... So where do I go from here?
DrBob222
You're right. It isn't MF3.
Do it this way.
delta T = i*Kb*m
If you let MFx ionize into M + xF, then
molar mass is 91+19x and
m = 90.5g/(91+19x)
Substitute delta T, for i substitute x+1, then Kb and m. Solve for x.
Do it this way.
delta T = i*Kb*m
If you let MFx ionize into M + xF, then
molar mass is 91+19x and
m = 90.5g/(91+19x)
Substitute delta T, for i substitute x+1, then Kb and m. Solve for x.
ANA
the answer should be ZrF4
someone
ZrF4 is wrong.
someone
This is an OLD question but I'm having trouble on it... *sigh*